-98j+24j^2=-8

Solution for -98j+24j^2=-8 equation:

-98j+24j^2=-8

We move all terms to the left:

-98j+24j^2-(-8)=0

We add all the numbers together, and all the variables

24j^2-98j+8=0

a = 24; b = -98; c = +8;
Δ = b2-4ac
Δ = -982-4·24·8
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-94}{2*24}=\frac{4}{48}
=1/12
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+94}{2*24}=\frac{192}{48}
=4
$